Solve for x
x=\frac{4\left(y-4\right)}{3}
Solve for y
y=\frac{3x}{4}+4
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-3x=16-4y
Subtract 4y from both sides.
\frac{-3x}{-3}=\frac{16-4y}{-3}
Divide both sides by -3.
x=\frac{16-4y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{4y-16}{3}
Divide 16-4y by -3.
4y=16+3x
Add 3x to both sides.
4y=3x+16
The equation is in standard form.
\frac{4y}{4}=\frac{3x+16}{4}
Divide both sides by 4.
y=\frac{3x+16}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{3x}{4}+4
Divide 16+3x by 4.
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