Solve for x
x=\frac{7y}{4}-2z
Solve for y
y=\frac{4\left(x+2z\right)}{7}
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4x+8z=7y
Add 7y to both sides. Anything plus zero gives itself.
4x=7y-8z
Subtract 8z from both sides.
\frac{4x}{4}=\frac{7y-8z}{4}
Divide both sides by 4.
x=\frac{7y-8z}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{7y}{4}-2z
Divide 7y-8z by 4.
-7y+8z=-4x
Subtract 4x from both sides. Anything subtracted from zero gives its negation.
-7y=-4x-8z
Subtract 8z from both sides.
\frac{-7y}{-7}=\frac{-4x-8z}{-7}
Divide both sides by -7.
y=\frac{-4x-8z}{-7}
Dividing by -7 undoes the multiplication by -7.
y=\frac{4x+8z}{7}
Divide -4x-8z by -7.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
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y = 3x + 4
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699 * 533
Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}