Solve for x
x=\frac{3y}{4}+\frac{1}{2}
Solve for y
y=\frac{4x-2}{3}
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4x-1=1+3y
Add 3y to both sides.
4x=1+3y+1
Add 1 to both sides.
4x=2+3y
Add 1 and 1 to get 2.
4x=3y+2
The equation is in standard form.
\frac{4x}{4}=\frac{3y+2}{4}
Divide both sides by 4.
x=\frac{3y+2}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3y}{4}+\frac{1}{2}
Divide 2+3y by 4.
-3y-1=1-4x
Subtract 4x from both sides.
-3y=1-4x+1
Add 1 to both sides.
-3y=2-4x
Add 1 and 1 to get 2.
\frac{-3y}{-3}=\frac{2-4x}{-3}
Divide both sides by -3.
y=\frac{2-4x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{4x-2}{3}
Divide 2-4x by -3.
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