Solve for x
x=\frac{3\left(y+4\right)}{4}
Solve for y
y=\frac{4\left(x-3\right)}{3}
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4x=12+3y
Add 3y to both sides.
4x=3y+12
The equation is in standard form.
\frac{4x}{4}=\frac{3y+12}{4}
Divide both sides by 4.
x=\frac{3y+12}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3y}{4}+3
Divide 12+3y by 4.
-3y=12-4x
Subtract 4x from both sides.
\frac{-3y}{-3}=\frac{12-4x}{-3}
Divide both sides by -3.
y=\frac{12-4x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{4x}{3}-4
Divide 12-4x by -3.
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