Solve for x
x=\frac{y+12}{4}
Solve for y
y=4\left(x-3\right)
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4x=y+9+3
Add 3 to both sides.
4x=y+12
Add 9 and 3 to get 12.
\frac{4x}{4}=\frac{y+12}{4}
Divide both sides by 4.
x=\frac{y+12}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{y}{4}+3
Divide y+12 by 4.
y+9=4x-3
Swap sides so that all variable terms are on the left hand side.
y=4x-3-9
Subtract 9 from both sides.
y=4x-12
Subtract 9 from -3 to get -12.
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Limits
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