Solve 4x-y^2-2y-3=0

$$4x- { y }^{ 2 } -2y-3=0$$

Solve for x

$$x=\frac{y^{2}+2y+3}{4}$$

Steps for Solving Linear Equation

Add y^{2} to both sides. Anything plus zero gives itself.

$$4x-2y-3=y^{2}$$

Add 2y to both sides.

$$4x-3=y^{2}+2y$$

Add 3 to both sides.

$$4x=y^{2}+2y+3$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{y^{2}+2y+3}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{y^{2}+2y+3}{4}$$

Divide y^{2}+2y+3 by 4.

$$x=\frac{y^{2}}{4}+\frac{y}{2}+\frac{3}{4}$$

Solve for y (complex solution)

$$y=-\sqrt{4x-2}-1$$

$$y=\sqrt{4x-2}-1$$

Solve for y

$$y=-\sqrt{4x-2}-1$$

$$y=\sqrt{4x-2}-1\text{, }x\geq \frac{1}{2}$$