Solve 4x-y/2+2x+2+5=-25/2+y

$$4x- \frac{ y }{ 2 } +2x+2+5=- \frac{ 25 }{ 2 } +y$$

Solve for x

$$x=\frac{y-13}{4}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$8x-y+4x+4+10=-25+2y$$

Combine 8x and 4x to get 12x.

$$12x-y+4+10=-25+2y$$

Add 4 and 10 to get 14.

$$12x-y+14=-25+2y$$

Add y to both sides.

$$12x+14=-25+2y+y$$

Combine 2y and y to get 3y.

$$12x+14=-25+3y$$

Subtract 14 from both sides.

$$12x=-25+3y-14$$

Subtract 14 from -25 to get -39.

$$12x=-39+3y$$

The equation is in standard form.

$$12x=3y-39$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{3y-39}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{3y-39}{12}$$

Divide -39+3y by 12.

$$x=\frac{y-13}{4}$$

Solve for y

$$y=4x+13$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$8x-y+4x+4+10=-25+2y$$

Combine 8x and 4x to get 12x.

$$12x-y+4+10=-25+2y$$

Add 4 and 10 to get 14.

$$12x-y+14=-25+2y$$

Subtract 2y from both sides.

$$12x-y+14-2y=-25$$

Subtract 12x from both sides.

$$-y+14-2y=-25-12x$$

Subtract 14 from both sides.

$$-y-2y=-25-12x-14$$

Subtract 14 from -25 to get -39.

$$-y-2y=-39-12x$$

Combine -y and -2y to get -3y.

$$-3y=-39-12x$$

The equation is in standard form.

$$-3y=-12x-39$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{-12x-39}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{-12x-39}{-3}$$

Divide -39-12x by -3.

$$y=4x+13$$