Solve for x
x=\frac{3z}{4}-\frac{7y}{4}+3
Solve for y
y=\frac{12+3z-4x}{7}
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4x-3z=12-7y
Subtract 7y from both sides.
4x=12-7y+3z
Add 3z to both sides.
4x=12+3z-7y
The equation is in standard form.
\frac{4x}{4}=\frac{12+3z-7y}{4}
Divide both sides by 4.
x=\frac{12+3z-7y}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3z}{4}-\frac{7y}{4}+3
Divide 12-7y+3z by 4.
7y-3z=12-4x
Subtract 4x from both sides.
7y=12-4x+3z
Add 3z to both sides.
7y=12+3z-4x
The equation is in standard form.
\frac{7y}{7}=\frac{12+3z-4x}{7}
Divide both sides by 7.
y=\frac{12+3z-4x}{7}
Dividing by 7 undoes the multiplication by 7.
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Limits
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