Solve 4x+6x+(19-x)*5+(19-x)*6=402/2

$$4x+6x+(19-x) \times 5+(19-x) \times 6= \frac{ 402 }{ 2 }$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Combine 4x and 6x to get 10x.

$$10x+\left(19-x\right)\times 5+\left(19-x\right)\times 6=\frac{402}{2}$$

Use the distributive property to multiply 19-x by 5.

$$10x+95-5x+\left(19-x\right)\times 6=\frac{402}{2}$$

Combine 10x and -5x to get 5x.

$$5x+95+\left(19-x\right)\times 6=\frac{402}{2}$$

Use the distributive property to multiply 19-x by 6.

$$5x+95+114-6x=\frac{402}{2}$$

Add 95 and 114 to get 209.

$$5x+209-6x=\frac{402}{2}$$

Combine 5x and -6x to get -x.

$$-x+209=\frac{402}{2}$$

Divide 402 by 2 to get 201.

$$-x+209=201$$

Subtract 209 from both sides.

$$-x=201-209$$

Subtract 209 from 201 to get -8.

$$-x=-8$$

Multiply both sides by -1.

$$x=8$$