Solve 4x+6(-19)/15=9

$$4x+6 \frac{ (-19) }{ 15 } = 9$$

Solve for x

$$x = \frac{83}{20} = 4\frac{3}{20} = 4.15$$

Steps for Solving Linear Equation

Fraction \frac{-19}{15} can be rewritten as -\frac{19}{15} by extracting the negative sign.

$$4x+6\left(-\frac{19}{15}\right)=9$$

Express 6\left(-\frac{19}{15}\right) as a single fraction.

$$4x+\frac{6\left(-19\right)}{15}=9$$

Multiply 6 and -19 to get -114.

$$4x+\frac{-114}{15}=9$$

Reduce the fraction \frac{-114}{15} to lowest terms by extracting and canceling out 3.

$$4x-\frac{38}{5}=9$$

Add \frac{38}{5} to both sides.

$$4x=9+\frac{38}{5}$$

Convert 9 to fraction \frac{45}{5}.

$$4x=\frac{45}{5}+\frac{38}{5}$$

Since \frac{45}{5} and \frac{38}{5} have the same denominator, add them by adding their numerators.

$$4x=\frac{45+38}{5}$$

Add 45 and 38 to get 83.

$$4x=\frac{83}{5}$$

Divide both sides by 4.

$$x=\frac{\frac{83}{5}}{4}$$

Express \frac{\frac{83}{5}}{4} as a single fraction.

$$x=\frac{83}{5\times 4}$$

Multiply 5 and 4 to get 20.

$$x=\frac{83}{20}$$