Solve for x
x=\frac{3y+19}{7}
Solve for y
y=\frac{7x-19}{3}
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7x+2y-5y=19
Combine 4x and 3x to get 7x.
7x-3y=19
Combine 2y and -5y to get -3y.
7x=19+3y
Add 3y to both sides.
7x=3y+19
The equation is in standard form.
\frac{7x}{7}=\frac{3y+19}{7}
Divide both sides by 7.
x=\frac{3y+19}{7}
Dividing by 7 undoes the multiplication by 7.
7x+2y-5y=19
Combine 4x and 3x to get 7x.
7x-3y=19
Combine 2y and -5y to get -3y.
-3y=19-7x
Subtract 7x from both sides.
\frac{-3y}{-3}=\frac{19-7x}{-3}
Divide both sides by -3.
y=\frac{19-7x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7x-19}{3}
Divide 19-7x by -3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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