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4x^{2}\times 5=32
Multiply x and x to get x^{2}.
20x^{2}=32
Multiply 4 and 5 to get 20.
x^{2}=\frac{32}{20}
Divide both sides by 20.
x^{2}=\frac{8}{5}
Reduce the fraction \frac{32}{20} to lowest terms by extracting and canceling out 4.
x=\frac{2\sqrt{10}}{5} x=-\frac{2\sqrt{10}}{5}
Take the square root of both sides of the equation.
4x^{2}\times 5=32
Multiply x and x to get x^{2}.
20x^{2}=32
Multiply 4 and 5 to get 20.
20x^{2}-32=0
Subtract 32 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 20\left(-32\right)}}{2\times 20}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 20 for a, 0 for b, and -32 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 20\left(-32\right)}}{2\times 20}
Square 0.
x=\frac{0±\sqrt{-80\left(-32\right)}}{2\times 20}
Multiply -4 times 20.
x=\frac{0±\sqrt{2560}}{2\times 20}
Multiply -80 times -32.
x=\frac{0±16\sqrt{10}}{2\times 20}
Take the square root of 2560.
x=\frac{0±16\sqrt{10}}{40}
Multiply 2 times 20.
x=\frac{2\sqrt{10}}{5}
Now solve the equation x=\frac{0±16\sqrt{10}}{40} when ± is plus.
x=-\frac{2\sqrt{10}}{5}
Now solve the equation x=\frac{0±16\sqrt{10}}{40} when ± is minus.
x=\frac{2\sqrt{10}}{5} x=-\frac{2\sqrt{10}}{5}
The equation is now solved.