Solve 4x*4*4y+2z=3

$$4x \times 4 \times 4y+2z=3$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{2z-3}{64y}\text{, }&y\neq 0\\x\in \mathrm{R}\text{, }&z=\frac{3}{2}\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 4 and 4 to get 16.

$$16x\times 4y+2z=3$$

Multiply 16 and 4 to get 64.

$$64xy+2z=3$$

Subtract 2z from both sides.

$$64xy=3-2z$$

The equation is in standard form.

$$64yx=3-2z$$

Divide both sides by 64y.

$$\frac{64yx}{64y}=\frac{3-2z}{64y}$$

Dividing by 64y undoes the multiplication by 64y.

$$x=\frac{3-2z}{64y}$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{2z-3}{64x}\text{, }&x\neq 0\\y\in \mathrm{R}\text{, }&z=\frac{3}{2}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 4 and 4 to get 16.

$$16x\times 4y+2z=3$$

Multiply 16 and 4 to get 64.

$$64xy+2z=3$$

Subtract 2z from both sides.

$$64xy=3-2z$$

Divide both sides by 64x.

$$\frac{64xy}{64x}=\frac{3-2z}{64x}$$

Dividing by 64x undoes the multiplication by 64x.

$$y=\frac{3-2z}{64x}$$