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\left(7t^{4}-5x^{5}\right)\left(7t^{4}+5x^{5}\right)
Rewrite 49t^{8}-25x^{10} as \left(7t^{4}\right)^{2}-\left(5x^{5}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-5x^{5}+7t^{4}\right)\left(5x^{5}+7t^{4}\right)
Reorder the terms.