Solve 48x+42y^2=0

$$48 x + 42 y ^ { 2 } = 0$$

Solve for x

$$x=-\frac{7y^{2}}{8}$$

Steps for Solving Linear Equation

Subtract 42y^{2} from both sides. Anything subtracted from zero gives its negation.

$$48x=-42y^{2}$$

Divide both sides by 48.

$$\frac{48x}{48}=-\frac{42y^{2}}{48}$$

Dividing by 48 undoes the multiplication by 48.

$$x=-\frac{42y^{2}}{48}$$

Divide -42y^{2} by 48.

$$x=-\frac{7y^{2}}{8}$$

Solve for y (complex solution)

$$y=-\frac{2i\sqrt{14x}}{7}$$

$$y=\frac{2i\sqrt{14x}}{7}$$

Solve for y

$$y=\frac{2\sqrt{-14x}}{7}$$

$$y=-\frac{2\sqrt{-14x}}{7}\text{, }x\leq 0$$