Solve 48*(7/12+1/4)

$$48 \times ( \frac { 7 } { 12 } + \frac { 1 } { 4 } )$$

Evaluate

$$40$$

Solution Steps

Least common multiple of 12 and 4 is 12. Convert \frac{7}{12} and \frac{1}{4} to fractions with denominator 12.

$$48\left(\frac{7}{12}+\frac{3}{12}\right)$$

Since \frac{7}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$48\times \frac{7+3}{12}$$

Add 7 and 3 to get 10.

$$48\times \frac{10}{12}$$

Reduce the fraction \frac{10}{12} to lowest terms by extracting and canceling out 2.

$$48\times \frac{5}{6}$$

Express 48\times \frac{5}{6} as a single fraction.

$$\frac{48\times 5}{6}$$

Multiply 48 and 5 to get 240.

$$\frac{240}{6}$$

Divide 240 by 6 to get 40.

$$40$$

Factor

$$2^{3}\times 5$$