Solve 48*(1/3-1/2+1/4)=

$$48 \times ( \frac{ 1 }{ 3 } - \frac{ 1 }{ 2 } + \frac{ 1 }{ 4 } )=$$

Evaluate

$$4$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$48\left(\frac{2}{6}-\frac{3}{6}+\frac{1}{4}\right)$$

Since \frac{2}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$48\left(\frac{2-3}{6}+\frac{1}{4}\right)$$

Subtract 3 from 2 to get -1.

$$48\left(-\frac{1}{6}+\frac{1}{4}\right)$$

Least common multiple of 6 and 4 is 12. Convert -\frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$48\left(-\frac{2}{12}+\frac{3}{12}\right)$$

Since -\frac{2}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$48\times \frac{-2+3}{12}$$

Add -2 and 3 to get 1.

$$48\times \frac{1}{12}$$

Multiply 48 and \frac{1}{12} to get \frac{48}{12}.

$$\frac{48}{12}$$

Divide 48 by 12 to get 4.

$$4$$

Factor

$$2^{2}$$