Solve 482/9+(-398/9)?

$$48 \frac { 2 } { 9 } + ( - 39 \frac { 8 } { 9 } ) ?$$

Evaluate

$$\frac{25}{3}\approx 8.333333333$$

Solution Steps

Multiply 48 and 9 to get 432.

$$\frac{432+2}{9}-\frac{39\times 9+8}{9}$$

Add 432 and 2 to get 434.

$$\frac{434}{9}-\frac{39\times 9+8}{9}$$

Multiply 39 and 9 to get 351.

$$\frac{434}{9}-\frac{351+8}{9}$$

Add 351 and 8 to get 359.

$$\frac{434}{9}-\frac{359}{9}$$

Since \frac{434}{9} and \frac{359}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{434-359}{9}$$

Subtract 359 from 434 to get 75.

$$\frac{75}{9}$$

Reduce the fraction \frac{75}{9} to lowest terms by extracting and canceling out 3.

$$\frac{25}{3}$$

Factor

$$\frac{5 ^ {2}}{3} = 8\frac{1}{3} = 8.333333333333334$$