Solve 48div(2^2*3)+138div23-18div3^2-10*4div8+125div5^2

$$48 \div ( 2 ^ { 2 } \cdot 3 ) + 138 \div 23 - 18 \div 3 ^ { 2 } - 10 \cdot 4 \div 8 + 125 \div 5 ^ { 2 }$$

Evaluate

$$8$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{48}{4\times 3}+\frac{138}{23}-\frac{18}{3^{2}}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Multiply 4 and 3 to get 12.

$$\frac{48}{12}+\frac{138}{23}-\frac{18}{3^{2}}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Divide 48 by 12 to get 4.

$$4+\frac{138}{23}-\frac{18}{3^{2}}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Divide 138 by 23 to get 6.

$$4+6-\frac{18}{3^{2}}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Add 4 and 6 to get 10.

$$10-\frac{18}{3^{2}}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$10-\frac{18}{9}-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Divide 18 by 9 to get 2.

$$10-2-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Subtract 2 from 10 to get 8.

$$8-\frac{10\times 4}{8}+\frac{125}{5^{2}}$$

Multiply 10 and 4 to get 40.

$$8-\frac{40}{8}+\frac{125}{5^{2}}$$

Divide 40 by 8 to get 5.

$$8-5+\frac{125}{5^{2}}$$

Subtract 5 from 8 to get 3.

$$3+\frac{125}{5^{2}}$$

Calculate 5 to the power of 2 and get 25.

$$3+\frac{125}{25}$$

Divide 125 by 25 to get 5.

$$3+5$$

Add 3 and 5 to get 8.

$$8$$

Factor

$$2^{3}$$