Solve 48:4^2+(4+3)*3-36:sqrt{34+2}=

$$48 : 4 ^ { 2 } + ( 4 + 3 ) \cdot 3 - 36 : \sqrt { 34 + 2 } =$$

Evaluate

$$18$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{48}{16}+\left(4+3\right)\times 3-\frac{36}{\sqrt{34+2}}$$

Divide 48 by 16 to get 3.

$$3+\left(4+3\right)\times 3-\frac{36}{\sqrt{34+2}}$$

Add 4 and 3 to get 7.

$$3+7\times 3-\frac{36}{\sqrt{34+2}}$$

Multiply 7 and 3 to get 21.

$$3+21-\frac{36}{\sqrt{34+2}}$$

Add 3 and 21 to get 24.

$$24-\frac{36}{\sqrt{34+2}}$$

Add 34 and 2 to get 36.

$$24-\frac{36}{\sqrt{36}}$$

Calculate the square root of 36 and get 6.

$$24-\frac{36}{6}$$

Divide 36 by 6 to get 6.

$$24-6$$

Subtract 6 from 24 to get 18.

$$18$$

Factor

$$2\times 3^{2}$$