Solve 48:{[29-(6*3+9)]*1+(2+28:7)}=

$$48 : \{ [ 29 - ( 6 \times 3 + 9 ) ] \times 1 + ( 2 + 28 : 7 ) \} =$$

Evaluate

$$6$$

Solution Steps

Multiply 6 and 3 to get 18.

$$\frac{48}{\left(29-\left(18+9\right)\right)\times 1+2+\frac{28}{7}}$$

Add 18 and 9 to get 27.

$$\frac{48}{\left(29-27\right)\times 1+2+\frac{28}{7}}$$

Subtract 27 from 29 to get 2.

$$\frac{48}{2\times 1+2+\frac{28}{7}}$$

Multiply 2 and 1 to get 2.

$$\frac{48}{2+2+\frac{28}{7}}$$

Add 2 and 2 to get 4.

$$\frac{48}{4+\frac{28}{7}}$$

Divide 28 by 7 to get 4.

$$\frac{48}{4+4}$$

Add 4 and 4 to get 8.

$$\frac{48}{8}$$

Divide 48 by 8 to get 6.

$$6$$

Factor

$$2\times 3$$