Solve 46=40+(30*5-2f1)div13

$$46 = 40+(30 \cdot 5-2f1) \div 13$$

Solve for f_1

$$f_{1}=36$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 13.

$$598=520+30\times 5-2f_{1}$$

Multiply 30 and 5 to get 150.

$$598=520+150-2f_{1}$$

Add 520 and 150 to get 670.

$$598=670-2f_{1}$$

Swap sides so that all variable terms are on the left hand side.

$$670-2f_{1}=598$$

Subtract 670 from both sides.

$$-2f_{1}=598-670$$

Subtract 670 from 598 to get -72.

$$-2f_{1}=-72$$

Divide both sides by -2.

$$f_{1}=\frac{-72}{-2}$$

Divide -72 by -2 to get 36.

$$f_{1}=36$$