Solve for x
x=-\frac{y}{15}+\frac{193}{45}
Solve for y
y=\frac{193}{3}-15x
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45x=193-3y
Subtract 3y from both sides.
\frac{45x}{45}=\frac{193-3y}{45}
Divide both sides by 45.
x=\frac{193-3y}{45}
Dividing by 45 undoes the multiplication by 45.
x=-\frac{y}{15}+\frac{193}{45}
Divide 193-3y by 45.
3y=193-45x
Subtract 45x from both sides.
\frac{3y}{3}=\frac{193-45x}{3}
Divide both sides by 3.
y=\frac{193-45x}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{193}{3}-15x
Divide 193-45x by 3.
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