Solve 45000+(1+.4147(20/24))

$$45000+(1+.4147( \frac{ 20 }{ 24 } ))$$

Evaluate

$$\frac{540016147}{12000}\approx 45001.345583333$$

Solution Steps

Add 45000 and 1 to get 45001.

$$45001+0.4147\times \frac{20}{24}$$

Reduce the fraction \frac{20}{24} to lowest terms by extracting and canceling out 4.

$$45001+0.4147\times \frac{5}{6}$$

Convert decimal number 0.4147 to fraction \frac{4147}{10000}.

$$45001+\frac{4147}{10000}\times \frac{5}{6}$$

Multiply \frac{4147}{10000} times \frac{5}{6} by multiplying numerator times numerator and denominator times denominator.

$$45001+\frac{4147\times 5}{10000\times 6}$$

Do the multiplications in the fraction \frac{4147\times 5}{10000\times 6}.

$$45001+\frac{20735}{60000}$$

Reduce the fraction \frac{20735}{60000} to lowest terms by extracting and canceling out 5.

$$45001+\frac{4147}{12000}$$

Convert 45001 to fraction \frac{540012000}{12000}.

$$\frac{540012000}{12000}+\frac{4147}{12000}$$

Since \frac{540012000}{12000} and \frac{4147}{12000} have the same denominator, add them by adding their numerators.

$$\frac{540012000+4147}{12000}$$

Add 540012000 and 4147 to get 540016147.

$$\frac{540016147}{12000}$$

Factor

$$\frac{11 \cdot 37 \cdot 1326821}{3 \cdot 2 ^ {5} \cdot 5 ^ {3}} = 45001\frac{4147}{12000} = 45001.345583333336$$