Solve for x
x\leq \frac{21}{5}
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45x-36-25x\leq 48
Subtract 25x from both sides.
20x-36\leq 48
Combine 45x and -25x to get 20x.
20x\leq 48+36
Add 36 to both sides.
20x\leq 84
Add 48 and 36 to get 84.
x\leq \frac{84}{20}
Divide both sides by 20. Since 20 is positive, the inequality direction remains the same.
x\leq \frac{21}{5}
Reduce the fraction \frac{84}{20} to lowest terms by extracting and canceling out 4.
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