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5\left(9x^{3}-49x\right)
Factor out 5.
x\left(9x^{2}-49\right)
Consider 9x^{3}-49x. Factor out x.
\left(3x-7\right)\left(3x+7\right)
Consider 9x^{2}-49. Rewrite 9x^{2}-49 as \left(3x\right)^{2}-7^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
5x\left(3x-7\right)\left(3x+7\right)
Rewrite the complete factored expression.