Solve 45-16*1.5(1+0.2)mgeq3

$$45 - 16 \times 1.5 ( 1 + 0.2 ) m \geq 3$$

Solve for m

$$m\leq \frac{35}{24}$$

Solution Steps

Multiply 16 and 1.5 to get 24.

$$45-24\left(1+0.2\right)m\geq 3$$

Add 1 and 0.2 to get 1.2.

$$45-24\times 1.2m\geq 3$$

Multiply 24 and 1.2 to get 28.8.

$$45-28.8m\geq 3$$

Subtract 45 from both sides.

$$-28.8m\geq 3-45$$

Subtract 45 from 3 to get -42.

$$-28.8m\geq -42$$

Divide both sides by -28.8. Since -28.8 is negative, the inequality direction is changed.

$$m\leq \frac{-42}{-28.8}$$

Expand \frac{-42}{-28.8} by multiplying both numerator and the denominator by 10.

$$m\leq \frac{-420}{-288}$$

Reduce the fraction \frac{-420}{-288} to lowest terms by extracting and canceling out -12.

$$m\leq \frac{35}{24}$$