Solve 45-{2-[5+4+(6-2)-(7+3-9)+6]-7}+8

$$45 - \{ 2 - [ 5 + 4 + ( 6 - 2 ) - ( 7 + 3 - 9 ) + 6 ] - 7 \} + 8$$

Evaluate

$$76$$

Solution Steps

Add 5 and 4 to get 9.

$$45-\left(2-\left(9+6-2-\left(7+3-9\right)+6\right)-7\right)+8$$

Add 9 and 6 to get 15.

$$45-\left(2-\left(15-2-\left(7+3-9\right)+6\right)-7\right)+8$$

Subtract 2 from 15 to get 13.

$$45-\left(2-\left(13-\left(7+3-9\right)+6\right)-7\right)+8$$

Add 7 and 3 to get 10.

$$45-\left(2-\left(13-\left(10-9\right)+6\right)-7\right)+8$$

Subtract 9 from 10 to get 1.

$$45-\left(2-\left(13-1+6\right)-7\right)+8$$

Subtract 1 from 13 to get 12.

$$45-\left(2-\left(12+6\right)-7\right)+8$$

Add 12 and 6 to get 18.

$$45-\left(2-18-7\right)+8$$

Subtract 18 from 2 to get -16.

$$45-\left(-16-7\right)+8$$

Subtract 7 from -16 to get -23.

$$45-\left(-23\right)+8$$

The opposite of -23 is 23.

$$45+23+8$$

Add 45 and 23 to get 68.

$$68+8$$

Add 68 and 8 to get 76.

$$76$$

Factor

$$2^{2}\times 19$$