Solve 45+13t>38t-3

$$45 + 13 t > 38 t - 3$$

Solve for t

$$t<\frac{48}{25}$$

Solution Steps

Subtract 38t from both sides.

$$45+13t-38t>-3$$

Combine 13t and -38t to get -25t.

$$45-25t>-3$$

Subtract 45 from both sides.

$$-25t>-3-45$$

Subtract 45 from -3 to get -48.

$$-25t>-48$$

Divide both sides by -25. Since -25 is negative, the inequality direction is changed.

$$t<\frac{-48}{-25}$$

Fraction \frac{-48}{-25} can be simplified to \frac{48}{25} by removing the negative sign from both the numerator and the denominator.

$$t<\frac{48}{25}$$