Evaluate
\frac{109273}{25}=4370.92
Factor
\frac{23 \cdot 4751}{5 ^ {2}} = 4370\frac{23}{25} = 4370.92
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4371-\frac{60}{1000}+\frac{40\times 2}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Multiply 20 and 3 to get 60.
4371-\frac{3}{50}+\frac{40\times 2}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Reduce the fraction \frac{60}{1000} to lowest terms by extracting and canceling out 20.
\frac{218550}{50}-\frac{3}{50}+\frac{40\times 2}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Convert 4371 to fraction \frac{218550}{50}.
\frac{218550-3}{50}+\frac{40\times 2}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Since \frac{218550}{50} and \frac{3}{50} have the same denominator, subtract them by subtracting their numerators.
\frac{218547}{50}+\frac{40\times 2}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Subtract 3 from 218550 to get 218547.
\frac{218547}{50}+\frac{80}{1000}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Multiply 40 and 2 to get 80.
\frac{218547}{50}+\frac{2}{25}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Reduce the fraction \frac{80}{1000} to lowest terms by extracting and canceling out 40.
\frac{218547}{50}+\frac{4}{50}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Least common multiple of 50 and 25 is 50. Convert \frac{218547}{50} and \frac{2}{25} to fractions with denominator 50.
\frac{218547+4}{50}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Since \frac{218547}{50} and \frac{4}{50} have the same denominator, add them by adding their numerators.
\frac{218551}{50}+\frac{20\times 3}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Add 218547 and 4 to get 218551.
\frac{218551}{50}+\frac{60}{1000}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Multiply 20 and 3 to get 60.
\frac{218551}{50}+\frac{3}{50}\times 2-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Reduce the fraction \frac{60}{1000} to lowest terms by extracting and canceling out 20.
\frac{218551}{50}+\frac{3\times 2}{50}-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Express \frac{3}{50}\times 2 as a single fraction.
\frac{218551}{50}+\frac{6}{50}-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Multiply 3 and 2 to get 6.
\frac{218551+6}{50}-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Since \frac{218551}{50} and \frac{6}{50} have the same denominator, add them by adding their numerators.
\frac{218557}{50}-\frac{20\times 2}{1000}\times 4-\frac{20\times 3}{1000}
Add 218551 and 6 to get 218557.
\frac{218557}{50}-\frac{40}{1000}\times 4-\frac{20\times 3}{1000}
Multiply 20 and 2 to get 40.
\frac{218557}{50}-\frac{1}{25}\times 4-\frac{20\times 3}{1000}
Reduce the fraction \frac{40}{1000} to lowest terms by extracting and canceling out 40.
\frac{218557}{50}-\frac{4}{25}-\frac{20\times 3}{1000}
Multiply \frac{1}{25} and 4 to get \frac{4}{25}.
\frac{218557}{50}-\frac{8}{50}-\frac{20\times 3}{1000}
Least common multiple of 50 and 25 is 50. Convert \frac{218557}{50} and \frac{4}{25} to fractions with denominator 50.
\frac{218557-8}{50}-\frac{20\times 3}{1000}
Since \frac{218557}{50} and \frac{8}{50} have the same denominator, subtract them by subtracting their numerators.
\frac{218549}{50}-\frac{20\times 3}{1000}
Subtract 8 from 218557 to get 218549.
\frac{218549}{50}-\frac{60}{1000}
Multiply 20 and 3 to get 60.
\frac{218549}{50}-\frac{3}{50}
Reduce the fraction \frac{60}{1000} to lowest terms by extracting and canceling out 20.
\frac{218549-3}{50}
Since \frac{218549}{50} and \frac{3}{50} have the same denominator, subtract them by subtracting their numerators.
\frac{218546}{50}
Subtract 3 from 218549 to get 218546.
\frac{109273}{25}
Reduce the fraction \frac{218546}{50} to lowest terms by extracting and canceling out 2.
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