Solve 43(x+2/5)=15

$$43 ( \frac { x + 2 } { 5 } ) = 15$$

Solve for x

$$x=-\frac{11}{43}\approx -0.255813953$$

Steps for Solving Linear Equation

Divide both sides by 43.

$$\frac{x+2}{5}=\frac{15}{43}$$

Multiply both sides by 5.

$$x+2=\frac{15}{43}\times 5$$

Express \frac{15}{43}\times 5 as a single fraction.

$$x+2=\frac{15\times 5}{43}$$

Multiply 15 and 5 to get 75.

$$x+2=\frac{75}{43}$$

Subtract 2 from both sides.

$$x=\frac{75}{43}-2$$

Convert 2 to fraction \frac{86}{43}.

$$x=\frac{75}{43}-\frac{86}{43}$$

Since \frac{75}{43} and \frac{86}{43} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{75-86}{43}$$

Subtract 86 from 75 to get -11.

$$x=-\frac{11}{43}$$