Solve 43+29*3-14*(5+4)+11+(14-3)-64div8*2

$$43 + 29 \times 3 - 14 \times ( 5 + 4 ) + 11 + ( 14 - 3 ) - 64 \div 8 \times 2$$

Evaluate

$$10$$

Solution Steps

Multiply 29 and 3 to get 87.

$$43+87-14\left(5+4\right)+11+14-3-\frac{64}{8}\times 2$$

Add 43 and 87 to get 130.

$$130-14\left(5+4\right)+11+14-3-\frac{64}{8}\times 2$$

Add 5 and 4 to get 9.

$$130-14\times 9+11+14-3-\frac{64}{8}\times 2$$

Multiply 14 and 9 to get 126.

$$130-126+11+14-3-\frac{64}{8}\times 2$$

Subtract 126 from 130 to get 4.

$$4+11+14-3-\frac{64}{8}\times 2$$

Add 4 and 11 to get 15.

$$15+14-3-\frac{64}{8}\times 2$$

Add 15 and 14 to get 29.

$$29-3-\frac{64}{8}\times 2$$

Subtract 3 from 29 to get 26.

$$26-\frac{64}{8}\times 2$$

Divide 64 by 8 to get 8.

$$26-8\times 2$$

Multiply 8 and 2 to get 16.

$$26-16$$

Subtract 16 from 26 to get 10.

$$10$$

Factor

$$2\times 5$$