Solve 428g=quadoperatorname{dkg}1

$$428 g = \quad \operatorname { dkg } 1$$

Solve for d

$$\left\{\begin{matrix}d=\frac{428g}{g_{1}k}\text{, }&g_{1}\neq 0\text{ and }k\neq 0\\d\in \mathrm{R}\text{, }&\left(g_{1}=0\text{ or }k=0\right)\text{ and }g=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$dkg_{1}=428g$$

The equation is in standard form.

$$g_{1}kd=428g$$

Divide both sides by kg_{1}.

$$\frac{g_{1}kd}{g_{1}k}=\frac{428g}{g_{1}k}$$

Dividing by kg_{1} undoes the multiplication by kg_{1}.

$$d=\frac{428g}{g_{1}k}$$

Solve for g

$$g=\frac{dg_{1}k}{428}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$428g=dg_{1}k$$

Divide both sides by 428.

$$\frac{428g}{428}=\frac{dg_{1}k}{428}$$

Dividing by 428 undoes the multiplication by 428.

$$g=\frac{dg_{1}k}{428}$$