Solve 42(8+4c)=32

$$42 ( 8 + 4 c ) = 32$$

Solve for c

$$c = -\frac{38}{21} = -1\frac{17}{21} \approx -1.80952381$$

Steps for Solving Linear Equation

Divide both sides by 42.

$$8+4c=\frac{32}{42}$$

Reduce the fraction \frac{32}{42} to lowest terms by extracting and canceling out 2.

$$8+4c=\frac{16}{21}$$

Subtract 8 from both sides.

$$4c=\frac{16}{21}-8$$

Convert 8 to fraction \frac{168}{21}.

$$4c=\frac{16}{21}-\frac{168}{21}$$

Since \frac{16}{21} and \frac{168}{21} have the same denominator, subtract them by subtracting their numerators.

$$4c=\frac{16-168}{21}$$

Subtract 168 from 16 to get -152.

$$4c=-\frac{152}{21}$$

Divide both sides by 4.

$$c=\frac{-\frac{152}{21}}{4}$$

Express \frac{-\frac{152}{21}}{4} as a single fraction.

$$c=\frac{-152}{21\times 4}$$

Multiply 21 and 4 to get 84.

$$c=\frac{-152}{84}$$

Reduce the fraction \frac{-152}{84} to lowest terms by extracting and canceling out 4.

$$c=-\frac{38}{21}$$