Solve 42a^2+36b-30=0

$$42 { a }^{ 2 } +36b-30 = 0$$

Solve for b

$$b=\frac{5-7a^{2}}{6}$$

Steps for Solving Linear Equation

Subtract 42a^{2} from both sides. Anything subtracted from zero gives its negation.

$$36b-30=-42a^{2}$$

Add 30 to both sides.

$$36b=-42a^{2}+30$$

The equation is in standard form.

$$36b=30-42a^{2}$$

Divide both sides by 36.

$$\frac{36b}{36}=\frac{30-42a^{2}}{36}$$

Dividing by 36 undoes the multiplication by 36.

$$b=\frac{30-42a^{2}}{36}$$

Divide -42a^{2}+30 by 36.

$$b=\frac{5-7a^{2}}{6}$$

Solve for a

$$a=\frac{\sqrt{35-42b}}{7}$$

$$a=-\frac{\sqrt{35-42b}}{7}\text{, }b\leq \frac{5}{6}$$