42 = 2 ( 2 a - 3 + c
Solve for a
a=-\frac{c}{2}+12
Solve for c
c=24-2a
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\frac{42}{2}=2a-3+c
Divide both sides by 2.
21=2a-3+c
Divide 42 by 2 to get 21.
2a-3+c=21
Swap sides so that all variable terms are on the left hand side.
2a+c=21+3
Add 3 to both sides.
2a+c=24
Add 21 and 3 to get 24.
2a=24-c
Subtract c from both sides.
\frac{2a}{2}=\frac{24-c}{2}
Divide both sides by 2.
a=\frac{24-c}{2}
Dividing by 2 undoes the multiplication by 2.
a=-\frac{c}{2}+12
Divide 24-c by 2.
\frac{42}{2}=2a-3+c
Divide both sides by 2.
21=2a-3+c
Divide 42 by 2 to get 21.
2a-3+c=21
Swap sides so that all variable terms are on the left hand side.
-3+c=21-2a
Subtract 2a from both sides.
c=21-2a+3
Add 3 to both sides.
c=24-2a
Add 21 and 3 to get 24.
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Limits
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