Solve 42+(-2/3)*(-3/4)div(-0.25)=

$$42 + ( - \frac { 2 } { 3 } ) \times ( - \frac { 3 } { 4 } ) \div ( - 0.25 ) =$$

Evaluate

$$40$$

Solution Steps

Multiply -\frac{2}{3} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$42+\frac{\frac{-2\left(-3\right)}{3\times 4}}{-0.25}$$

Do the multiplications in the fraction \frac{-2\left(-3\right)}{3\times 4}.

$$42+\frac{\frac{6}{12}}{-0.25}$$

Reduce the fraction \frac{6}{12} to lowest terms by extracting and canceling out 6.

$$42+\frac{\frac{1}{2}}{-0.25}$$

Express \frac{\frac{1}{2}}{-0.25} as a single fraction.

$$42+\frac{1}{2\left(-0.25\right)}$$

Multiply 2 and -0.25 to get -0.5.

$$42+\frac{1}{-0.5}$$

Expand \frac{1}{-0.5} by multiplying both numerator and the denominator by 10.

$$42+\frac{10}{-5}$$

Divide 10 by -5 to get -2.

$$42-2$$

Subtract 2 from 42 to get 40.

$$40$$

Factor

$$5\times 2^{3}$$