Solve 41.89^{2}*c^{2}+c^4/16*2.4^2=34^2/0.37^2

Solve for c (complex solution)

c=\frac{i\times 2\sqrt{222\left(\sqrt{3794364836472414961}+1947797031\right)}}{4625}\approx 402.14998282i

c=-\frac{i\times 2\sqrt{222\left(\sqrt{3794364836472414961}+1947797031\right)}}{4625}\approx -0-402.14998282i

c = -\frac{2 \sqrt{222 {(\sqrt{3794364836472414961} - 1947797031)}}}{4625} \approx -2.19361482

c = \frac{2 \sqrt{222 {(\sqrt{3794364836472414961} - 1947797031)}}}{4625} \approx 2.19361482

Solve for c

c = -\frac{2 \sqrt{222 {(\sqrt{3794364836472414961} - 1947797031)}}}{4625} \approx -2.19361482

c = \frac{2 \sqrt{222 {(\sqrt{3794364836472414961} - 1947797031)}}}{4625} \approx 2.19361482

Quiz

Polynomial

5 problems similar to:

41.89 ^ { 2 } \cdot c ^ { 2 } + \frac { c ^ { 4 } } { 16 \times 2.4 ^ { 2 } } = \frac { 34 ^ { 2 } } { 0.37 ^ { 2 } }

Similar Problems from Web Search

Prove that 1^2\cdot3^2\cdot5^2\cdots(p-2)^2 \equiv (-1)^{(p+1)/2} \pmod p [duplicate]

https://math.stackexchange.com/q/2837357

Multiply both sides by (p-1)^2 for the equivalent: 1 = (p-1)^2 (-1)^{(p+1)/2} \text{ mod } p where the left hand side was (the product of all nonzero elements modulo p)^2 \equiv^{\star} (-1)^2 = 1 ...

The Laurent Series of \dfrac{e^z}{z^2-1}

https://math.stackexchange.com/questions/1378932/the-laurent-series-of-dfracezz2-1

We can use Cauchy product ( Cauchy product ) to calculate the product series but first we need to correct the Laurent development of \frac{1}{z^2-1}: \begin{eqnarray} ...

Conditional distribution of multivariate Rayleigh distribution

https://math.stackexchange.com/q/2808131

Well, now I think the above conditional Rician PDF is false, which means it's a mistake in Appendix I of the paper, and it really misleads my further calculation. When X_0 and Y_0 are fixed, mean ...

Why is the square of all odds less than an odd prime p congruent to (-1)^{(p+1)/(2)}\pmod p?

https://math.stackexchange.com/q/4827

Modulo p, you have k=-(p-k) and so both products are equal to (p-1)!(-1)^{(p-1)/2} \equiv (-1)^{(p+1)/2} \pmod{p} by Wilson's theorem.

Bessel functions in resolution of second order ODE

https://math.stackexchange.com/questions/2253053/bessel-functions-in-resolution-of-second-order-ode

Your equation may be written as r^2 v''(r)+rv'(r)-wr^2 v(r) = 0. You are interested in solutions for w > 0. It turns out that, if you find a solution f(r) for w=1, then v(r)=f(\sqrt{w}r) ...

How to best calculate Christoffel symbols of metric du^2 +g^2(u) dv^2?

https://math.stackexchange.com/questions/1720424/how-to-best-calculate-christoffel-symbols-of-metric-du2-g2u-dv2

The way that I calculate Christoffel symbols (when I must) is using this formula: \Gamma^{i}_{jk}=\sum_{m=1}^2\frac{1}{2}(g^{-1})^{im}\left(\frac{\partial g_{mj}}{\partial x^k}+\frac{\partial g_{mk}}{\partial x^j}-\frac{\partial g_{jk}}{\partial x^m}\right), ...

Copied to clipboard

Examples

Quadratic equation

{ x } ^ { 2 } - 4 x - 5 = 0

Trigonometry

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Simultaneous equation

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Differentiation

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Integration

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Limits

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

Topics

Topics

Similar Problems from Web Search

Share

Examples