Solve 41-3/4xleq53

$$41 - 3 / 4 x \leq 53$$

Solve for x

$$x\geq -16$$

Solution Steps

Subtract 41 from both sides.

$$-\frac{3}{4}x\leq 53-41$$

Subtract 41 from 53 to get 12.

$$-\frac{3}{4}x\leq 12$$

Multiply both sides by -\frac{4}{3}, the reciprocal of -\frac{3}{4}. Since -\frac{3}{4} is negative, the inequality direction is changed.

$$x\geq 12\left(-\frac{4}{3}\right)$$

Express 12\left(-\frac{4}{3}\right) as a single fraction.

$$x\geq \frac{12\left(-4\right)}{3}$$

Multiply 12 and -4 to get -48.

$$x\geq \frac{-48}{3}$$

Divide -48 by 3 to get -16.

$$x\geq -16$$