Solve 41/2/3+6*3/5

$$41 / \frac { 2 } { 3 } + 6 \times \frac { 3 } { 5 }$$

Evaluate

$$\frac{651}{10}=65.1$$

Solution Steps

Divide 41 by \frac{2}{3} by multiplying 41 by the reciprocal of \frac{2}{3}.

$$41\times \frac{3}{2}+6\times \frac{3}{5}$$

Express 41\times \frac{3}{2} as a single fraction.

$$\frac{41\times 3}{2}+6\times \frac{3}{5}$$

Multiply 41 and 3 to get 123.

$$\frac{123}{2}+6\times \frac{3}{5}$$

Express 6\times \frac{3}{5} as a single fraction.

$$\frac{123}{2}+\frac{6\times 3}{5}$$

Multiply 6 and 3 to get 18.

$$\frac{123}{2}+\frac{18}{5}$$

Least common multiple of 2 and 5 is 10. Convert \frac{123}{2} and \frac{18}{5} to fractions with denominator 10.

$$\frac{615}{10}+\frac{36}{10}$$

Since \frac{615}{10} and \frac{36}{10} have the same denominator, add them by adding their numerators.

$$\frac{615+36}{10}$$

Add 615 and 36 to get 651.

$$\frac{651}{10}$$

Factor

$$\frac{3 \cdot 7 \cdot 31}{2 \cdot 5} = 65\frac{1}{10} = 65.1$$