Solve 40x+zy=298

$$40x+zy=298$$

Solve for x

$$x=-\frac{yz}{40}+\frac{149}{20}$$

Steps for Solving Linear Equation

Subtract zy from both sides.

$$40x=298-zy$$

The equation is in standard form.

$$40x=298-yz$$

Divide both sides by 40.

$$\frac{40x}{40}=\frac{298-yz}{40}$$

Dividing by 40 undoes the multiplication by 40.

$$x=\frac{298-yz}{40}$$

Divide 298-zy by 40.

$$x=-\frac{yz}{40}+\frac{149}{20}$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{2\left(20x-149\right)}{z}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&x=\frac{149}{20}\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 40x from both sides.

$$zy=298-40x$$

Divide both sides by z.

$$\frac{zy}{z}=\frac{298-40x}{z}$$

Dividing by z undoes the multiplication by z.

$$y=\frac{298-40x}{z}$$

Divide 298-40x by z.

$$y=\frac{2\left(149-20x\right)}{z}$$