Solve for x
x<\frac{35}{2}
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40x+1300<2000
Multiply 65 and 20 to get 1300.
40x<2000-1300
Subtract 1300 from both sides.
40x<700
Subtract 1300 from 2000 to get 700.
x<\frac{700}{40}
Divide both sides by 40. Since 40 is positive, the inequality direction remains the same.
x<\frac{35}{2}
Reduce the fraction \frac{700}{40} to lowest terms by extracting and canceling out 20.
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