Solve 40x+4x1=32.x1+x=2

$$40x+4x1 = 32.x1+x=2$$

Solve for x

$$x=-\frac{x_{1}}{10}+\frac{4}{5}$$

Steps for Solving Linear Equation

Subtract 4x_{1} from both sides.

$$40x=32-4x_{1}$$

Divide both sides by 40.

$$\frac{40x}{40}=\frac{32-4x_{1}}{40}$$

Dividing by 40 undoes the multiplication by 40.

$$x=\frac{32-4x_{1}}{40}$$

Divide 32-4x_{1} by 40.

$$x=-\frac{x_{1}}{10}+\frac{4}{5}$$

Solve for x_1

$$x_{1}=8-10x$$

Steps for Solving Linear Equation

Subtract 40x from both sides.

$$4x_{1}=32-40x$$

Divide both sides by 4.

$$\frac{4x_{1}}{4}=\frac{32-40x}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x_{1}=\frac{32-40x}{4}$$

Divide 32-40x by 4.

$$x_{1}=8-10x$$