Solve 402+[1002:3-(100+2)*2]:1*4=408

$$402 + [ 1002 : 3 - ( 100 + 2 ) \times 2 ] : 1 \cdot 4 = 408$$

Verify

Solution Steps

Divide 1002 by 3 to get 334.

$$402+\frac{334-\left(100+2\right)\times 2}{1}\times 4=408$$

Add 100 and 2 to get 102.

$$402+\frac{334-102\times 2}{1}\times 4=408$$

Multiply 102 and 2 to get 204.

$$402+\frac{334-204}{1}\times 4=408$$

Subtract 204 from 334 to get 130.

$$402+\frac{130}{1}\times 4=408$$

Anything divided by one gives itself.

$$402+130\times 4=408$$

Multiply 130 and 4 to get 520.

$$402+520=408$$

Add 402 and 520 to get 922.

$$922=408$$

Compare 922 and 408.

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