Solve 4000-(12^2-6^2)+102*0-990:99

$$4000 - ( 12 ^ { 2 } - 6 ^ { 2 } ) + 102 \cdot 0 - 990 : 99$$

Evaluate

$$3882$$

Solution Steps

Calculate 12 to the power of 2 and get 144.

$$4000-\left(144-6^{2}\right)+102\times 0-\frac{990}{99}$$

Calculate 6 to the power of 2 and get 36.

$$4000-\left(144-36\right)+102\times 0-\frac{990}{99}$$

Subtract 36 from 144 to get 108.

$$4000-108+102\times 0-\frac{990}{99}$$

Subtract 108 from 4000 to get 3892.

$$3892+102\times 0-\frac{990}{99}$$

Multiply 102 and 0 to get 0.

$$3892+0-\frac{990}{99}$$

Add 3892 and 0 to get 3892.

$$3892-\frac{990}{99}$$

Divide 990 by 99 to get 10.

$$3892-10$$

Subtract 10 from 3892 to get 3882.

$$3882$$

Factor

$$2\times 3\times 647$$