Solve 4000(1+4.4/4)^4(9)

$$4000 ( 1 + \frac { 4.4 } { 4 } ) ^ { 4 ( 9 ) }$$

Evaluate

$$1592042296860430.717688235542403344244835778290884$$

Solution Steps

Expand \frac{4.4}{4} by multiplying both numerator and the denominator by 10.

$$4000\left(1+\frac{44}{40}\right)^{4\times 9}$$

Reduce the fraction \frac{44}{40} to lowest terms by extracting and canceling out 4.

$$4000\left(1+\frac{11}{10}\right)^{4\times 9}$$

Add 1 and \frac{11}{10} to get \frac{21}{10}.

$$4000\times \left(\frac{21}{10}\right)^{4\times 9}$$

Multiply 4 and 9 to get 36.

$$4000\times \left(\frac{21}{10}\right)^{36}$$

Calculate \frac{21}{10} to the power of 36 and get \frac{398010574215107679422058885600836061208944572721}{1000000000000000000000000000000000000}.

$$4000\times \frac{398010574215107679422058885600836061208944572721}{1000000000000000000000000000000000000}$$

Multiply 4000 and \frac{398010574215107679422058885600836061208944572721}{1000000000000000000000000000000000000} to get \frac{398010574215107679422058885600836061208944572721}{250000000000000000000000000000000}.

$$\frac{398010574215107679422058885600836061208944572721}{250000000000000000000000000000000}$$

Factor

$$\frac{3 ^ {36} \cdot 7 ^ {36}}{2 ^ {31} \cdot 5 ^ {33}} = 1592042296860431\frac{2.413422789925954 \times 10^{32}}{2.4999999999999996 \times 10^{32}} = 1592042296860431$$