Solve 4000+100(x-12)=6400+(x-12)

$$4000 + 100 ( x - 12 ) = 6400 + ( x - 12 )$$

Solve for x

$$x = \frac{1196}{33} = 36\frac{8}{33} \approx 36.242424242$$

Steps for Solving Linear Equation

Use the distributive property to multiply 100 by x-12.

$$4000+100x-1200=6400+x-12$$

Subtract 1200 from 4000 to get 2800.

$$2800+100x=6400+x-12$$

Subtract 12 from 6400 to get 6388.

$$2800+100x=6388+x$$

Subtract x from both sides.

$$2800+100x-x=6388$$

Combine 100x and -x to get 99x.

$$2800+99x=6388$$

Subtract 2800 from both sides.

$$99x=6388-2800$$

Subtract 2800 from 6388 to get 3588.

$$99x=3588$$

Divide both sides by 99.

$$x=\frac{3588}{99}$$

Reduce the fraction \frac{3588}{99} to lowest terms by extracting and canceling out 3.

$$x=\frac{1196}{33}$$