Solve 400(1-y)^2=324

$$400 ( 1 - y ) ^ { 2 } = 324$$

Solve for y

$$y=\frac{1}{10}=0.1$$

$$y = \frac{19}{10} = 1\frac{9}{10} = 1.9$$

Steps by Finding Square Root

Divide both sides by 400.

$$\frac{400\left(-y+1\right)^{2}}{400}=\frac{324}{400}$$

Dividing by 400 undoes the multiplication by 400.

$$\left(-y+1\right)^{2}=\frac{324}{400}$$

Reduce the fraction \frac{324}{400} to lowest terms by extracting and canceling out 4.

$$\left(-y+1\right)^{2}=\frac{81}{100}$$

Take the square root of both sides of the equation.

$$-y+1=\frac{9}{10} -y+1=-\frac{9}{10}$$

Subtract 1 from both sides of the equation.

$$-y+1-1=\frac{9}{10}-1 -y+1-1=-\frac{9}{10}-1$$

Subtracting 1 from itself leaves 0.

$$-y=\frac{9}{10}-1 -y=-\frac{9}{10}-1$$

Subtract 1 from \frac{9}{10}.

$$-y=-\frac{1}{10}$$

Subtract 1 from -\frac{9}{10}.

$$-y=-\frac{19}{10}$$

Divide both sides by -1.

$$\frac{-y}{-1}=-\frac{\frac{1}{10}}{-1} \frac{-y}{-1}=-\frac{\frac{19}{10}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=-\frac{\frac{1}{10}}{-1} y=-\frac{\frac{19}{10}}{-1}$$

Divide -\frac{1}{10} by -1.

$$y=\frac{1}{10}$$

Divide -\frac{19}{10} by -1.

$$y=\frac{19}{10}$$

The equation is now solved.

$$y=\frac{1}{10} y=\frac{19}{10}$$