Solve 40-lceil5^2+(2^3-7)rceil

$$40- \lceil { 5 }^{ 2 } +( { 2 }^{ 3 } -7) \rceil$$

Evaluate

$$14$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$40-\lceil 25+2^{3}-7\rceil$$

Calculate 2 to the power of 3 and get 8.

$$40-\lceil 25+8-7\rceil$$

Add 25 and 8 to get 33.

$$40-\lceil 33-7\rceil$$

Subtract 7 from 33 to get 26.

$$40-\lceil 26\rceil$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 26 is 26.

$$40-26$$

Subtract 26 from 40 to get 14.

$$14$$

Factor

$$2\times 7$$