Solve 40-frac{40sqrt{3}}{3}

$$40- \frac{ 40 \sqrt{ 3 } }{ 3 }$$

Evaluate

$$-\frac{40\sqrt{3}}{3}+40\approx 16.905989232$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 40 times \frac{3}{3}.

$$\frac{40\times 3}{3}-\frac{40\sqrt{3}}{3}$$

Since \frac{40\times 3}{3} and \frac{40\sqrt{3}}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40\times 3-40\sqrt{3}}{3}$$

Do the multiplications in 40\times 3-40\sqrt{3}.

$$\frac{120-40\sqrt{3}}{3}$$

Factor

$$\frac{40 \sqrt{3} {(\sqrt{3} - 1)}}{3} = 16.905989232414964$$